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Read XML Attribute using XmlDocument


Question

How can I read an XML attribute using C#'s XmlDocument?

I have an XML file which looks somewhat like this:

<?xml version="1.0" encoding="utf-8" ?>
<MyConfiguration xmlns="http://tempuri.org/myOwnSchema.xsd" SuperNumber="1" SuperString="whipcream">
    <Other stuff />
</MyConfiguration> 

How would I read the XML attributes SuperNumber and SuperString?

Currently I'm using XmlDocument, and I get the values in between using XmlDocument's GetElementsByTagName() and that works really well. I just can't figure out how to get the attributes?

2013/01/11
1
79
1/11/2013 2:27:39 PM

Accepted Answer

XmlNodeList elemList = doc.GetElementsByTagName(...);
for (int i = 0; i < elemList.Count; i++)
{
    string attrVal = elemList[i].Attributes["SuperString"].Value;
}
2017/09/21
113
9/21/2017 8:10:51 AM


You can migrate to XDocument instead of XmlDocument and then use Linq if you prefer that syntax. Something like:

var q = (from myConfig in xDoc.Elements("MyConfiguration")
         select myConfig.Attribute("SuperString").Value)
         .First();
2009/06/01

I have an Xml File books.xml

<ParameterDBConfig>
    <ID Definition="1" />
</ParameterDBConfig>

Program:

XmlDocument doc = new XmlDocument();
doc.Load("D:/siva/books.xml");
XmlNodeList elemList = doc.GetElementsByTagName("ID");     
for (int i = 0; i < elemList.Count; i++)     
{
    string attrVal = elemList[i].Attributes["Definition"].Value;
}

Now, attrVal has the value of ID.

2012/06/05

XmlDocument.Attributes perhaps? (Which has a method GetNamedItem that will presumably do what you want, although I've always just iterated the attribute collection)

2009/06/01

Assuming your example document is in the string variable doc

> XDocument.Parse(doc).Root.Attribute("SuperNumber")
1
2013/03/17

If your XML contains namespaces, then you can do the following in order to obtain the value of an attribute:

var xmlDoc = new XmlDocument();

// content is your XML as string
xmlDoc.LoadXml(content);

XmlNamespaceManager nsmgr = new XmlNamespaceManager(new NameTable());

// make sure the namespace identifier, URN in this case, matches what you have in your XML 
nsmgr.AddNamespace("ns", "urn:oasis:names:tc:SAML:2.0:protocol");

// get the value of Destination attribute from within the Response node with a prefix who's identifier is "urn:oasis:names:tc:SAML:2.0:protocol" using XPath
var str = xmlDoc.SelectSingleNode("/ns:Response/@Destination", nsmgr);
if (str != null)
{
    Console.WriteLine(str.Value);
}

More on XML namespaces here and here.

2016/03/01

Source: https://stackoverflow.com/questions/933687
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