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grep a file, but show several surrounding lines?


Question

I would like to grep for a string, but also show the preceding five lines and the following five lines as well as the matched line. How would I be able to do this?

2017/05/31
1
3488
5/31/2017 2:44:15 AM

Accepted Answer

For BSD or GNU grep you can use -B num to set how many lines before the match and -A num for the number of lines after the match.

grep -B 3 -A 2 foo README.txt

If you want the same number of lines before and after you can use -C num.

grep -C 3 foo README.txt

This will show 3 lines before and 3 lines after.

2017/09/21
4626
9/21/2017 8:33:54 AM

-A and -B will work, as will -C n (for n lines of context), or just -n (for n lines of context... as long as n is 1 to 9).

2019/04/03

ack works with similar arguments as grep, and accepts -C. But it's usually better for searching through code.

2017/01/06

grep astring myfile -A 5 -B 5

That will grep "myfile" for "astring", and show 5 lines before and after each match

2008/08/12

I normally use

grep searchstring file -C n # n for number of lines of context up and down

Many of the tools like grep also have really great man files too. I find myself referring to grep's man page a lot because there is so much you can do with it.

man grep

Many GNU tools also have an info page that may have more useful information in addition to the man page.

info grep
2020/07/05

Use grep

$ grep --help | grep -i context
Context control:
  -B, --before-context=NUM  print NUM lines of leading context
  -A, --after-context=NUM   print NUM lines of trailing context
  -C, --context=NUM         print NUM lines of output context
  -NUM                      same as --context=NUM
2018/01/12

Source: https://stackoverflow.com/questions/9081
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