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How to check a not-defined variable in JavaScript


Question

I wanted to check whether the variable is defined or not. For example, the following throws a not-defined error

alert( x );

How can I catch this error?

2017/03/03
1
925
3/3/2017 7:35:58 PM

Accepted Answer

In JavaScript, null is an object. There's another value for things that don't exist, undefined. The DOM returns null for almost all cases where it fails to find some structure in the document, but in JavaScript itself undefined is the value used.

Second, no, there is not a direct equivalent. If you really want to check for specifically for null, do:

if (yourvar === null) // Does not execute if yourvar is `undefined`

If you want to check if a variable exists, that can only be done with try/catch, since typeof will treat an undeclared variable and a variable declared with the value of undefined as equivalent.

But, to check if a variable is declared and is not undefined:

if (yourvar !== undefined) // Any scope

Previously, it was necessary to use the typeof operator to check for undefined safely, because it was possible to reassign undefined just like a variable. The old way looked like this:

if (typeof yourvar !== 'undefined') // Any scope

The issue of undefined being re-assignable was fixed in ECMAScript 5, which was released in 2009. You can now safely use === and !== to test for undefined without using typeof as undefined has been read-only for some time.

If you want to know if a member exists independent but don't care what its value is:

if ('membername' in object) // With inheritance
if (object.hasOwnProperty('membername')) // Without inheritance

If you want to to know whether a variable is truthy:

if (yourvar)

Source

2020/03/27
1703
3/27/2020 6:10:14 AM

The only way to truly test if a variable is undefined is to do the following. Remember, undefined is an object in JavaScript.

if (typeof someVar === 'undefined') {
  // Your variable is undefined
}

Some of the other solutions in this thread will lead you to believe a variable is undefined even though it has been defined (with a value of NULL or 0, for instance).

2014/11/23

Technically, the proper solution is (I believe):

typeof x === "undefined"

You can sometimes get lazy and use

x == null

but that allows both an undefined variable x, and a variable x containing null, to return true.

2014/11/23

An even easier and more shorthand version would be:

if (!x) {
   //Undefined
}

OR

if (typeof x !== "undefined") {
    //Do something since x is defined.
}
2014/11/23

I've often done:

function doSomething(variable)
{
    var undef;

    if(variable === undef)
    {
         alert('Hey moron, define this bad boy.');
    }
}
2014/04/24

You can also use the ternary conditional-operator:

var a = "hallo world";
var a = !a ? document.write("i dont know 'a'") : document.write("a = " + a);

//var a = "hallo world";
var a = !a ? document.write("i dont know 'a'") : document.write("a = " + a);

2016/02/12

Source: https://stackoverflow.com/questions/858181
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