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Proxies with Python 'Requests' module


Question

Just a short, simple one about the excellent Requests module for Python.

I can't seem to find in the documentation what the variable 'proxies' should contain. When I send it a dict with a standard "IP:PORT" value it rejected it asking for 2 values. So, I guess (because this doesn't seem to be covered in the docs) that the first value is the ip and the second the port?

The docs mention this only:

proxies – (optional) Dictionary mapping protocol to the URL of the proxy.

So I tried this... what should I be doing?

proxy = { ip: port}

and should I convert these to some type before putting them in the dict?

r = requests.get(url,headers=headers,proxies=proxy)
2012/04/07
1
164
4/7/2012 11:44:12 AM

Accepted Answer

The proxies' dict syntax is {"protocol":"ip:port", ...}. With it you can specify different (or the same) proxie(s) for requests using http, https, and ftp protocols:

http_proxy  = "http://10.10.1.10:3128"
https_proxy = "https://10.10.1.11:1080"
ftp_proxy   = "ftp://10.10.1.10:3128"

proxyDict = { 
              "http"  : http_proxy, 
              "https" : https_proxy, 
              "ftp"   : ftp_proxy
            }

r = requests.get(url, headers=headers, proxies=proxyDict)

Deduced from the requests documentation:

Parameters:
method – method for the new Request object.
url – URL for the new Request object.
...
proxies – (optional) Dictionary mapping protocol to the URL of the proxy.
...


On linux you can also do this via the HTTP_PROXY, HTTPS_PROXY, and FTP_PROXY environment variables:

export HTTP_PROXY=10.10.1.10:3128
export HTTPS_PROXY=10.10.1.11:1080
export FTP_PROXY=10.10.1.10:3128

On Windows:

set http_proxy=10.10.1.10:3128
set https_proxy=10.10.1.11:1080
set ftp_proxy=10.10.1.10:3128

Thanks, Jay for pointing this out:
The syntax changed with requests 2.0.0.
You'll need to add a schema to the url: https://2.python-requests.org/en/latest/user/advanced/#proxies

2020/05/07
288
5/7/2020 12:25:52 PM

I have found that urllib has some really good code to pick up the system's proxy settings and they happen to be in the correct form to use directly. You can use this like:

import urllib

...
r = requests.get('http://example.org', proxies=urllib.request.getproxies())

It works really well and urllib knows about getting Mac OS X and Windows settings as well.

2019/03/05

You can refer to the proxy documentation here.

If you need to use a proxy, you can configure individual requests with the proxies argument to any request method:

import requests

proxies = {
  "http": "http://10.10.1.10:3128",
  "https": "https://10.10.1.10:1080",
}

requests.get("http://example.org", proxies=proxies)

To use HTTP Basic Auth with your proxy, use the http://user:[email protected]/ syntax:

proxies = {
    "http": "http://user:[email protected]:3128/"
}
2019/03/05

The accepted answer was a good start for me, but I kept getting the following error:

AssertionError: Not supported proxy scheme None

Fix to this was to specify the http:// in the proxy url thus:

http_proxy  = "http://194.62.145.248:8080"
https_proxy  = "https://194.62.145.248:8080"
ftp_proxy   = "10.10.1.10:3128"

proxyDict = {
              "http"  : http_proxy,
              "https" : https_proxy,
              "ftp"   : ftp_proxy
            }

I'd be interested as to why the original works for some people but not me.

Edit: I see the main answer is now updated to reflect this :)

2015/02/14

8 years late. But I like:

import os
import requests

os.environ['HTTP_PROXY'] = os.environ['http_proxy'] = 'http://http-connect-proxy:3128/'
os.environ['HTTPS_PROXY'] = os.environ['https_proxy'] = 'http://http-connect-proxy:3128/'
os.environ['NO_PROXY'] = os.environ['no_proxy'] = '127.0.0.1,localhost,.local'

r = requests.get('https://example.com')  # , verify=False
2020/02/22

If you'd like to persisist cookies and session data, you'd best do it like this:

import requests

proxies = {
    'http': 'http://user:[email protected]:3128',
    'https': 'https://user:[email protected]:3128',
}

# Create the session and set the proxies.
s = requests.Session()
s.proxies = proxies

# Make the HTTP request through the session.
r = s.get('http://www.showmemyip.com/')
2018/11/30

Source: https://stackoverflow.com/questions/8287628
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