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How to find if an array contains a specific string in JavaScript/jQuery?


Question

Can someone tell me how to detect if "specialword" appears in an array? Example:

categories: [
    "specialword"
    "word1"
    "word2"
]
2017/11/08
1
618
11/8/2017 3:36:39 PM

Accepted Answer

You really don't need jQuery for this.

var myarr = ["I", "like", "turtles"];
var arraycontainsturtles = (myarr.indexOf("turtles") > -1);

Hint: indexOf returns a number, representing the position where the specified searchvalue occurs for the first time, or -1 if it never occurs

or

function arrayContains(needle, arrhaystack)
{
    return (arrhaystack.indexOf(needle) > -1);
}

It's worth noting that array.indexOf(..) is not supported in IE < 9, but jQuery's indexOf(...) function will work even for those older versions.

2018/11/26
973
11/26/2018 11:35:47 AM


Here you go:

$.inArray('specialword', arr)

This function returns a positive integer (the array index of the given value), or -1 if the given value was not found in the array.

Live demo: http://jsfiddle.net/simevidas/5Gdfc/

You probably want to use this like so:

if ( $.inArray('specialword', arr) > -1 ) {
    // the value is in the array
}
2011/05/24

You can use a for loop:

var found = false;
for (var i = 0; i < categories.length && !found; i++) {
  if (categories[i] === "specialword") {
    found = true;
    break;
  }
}
2017/05/21

I don't like $.inArray(..), it's the kind of ugly, jQuery-ish solution that most sane people wouldn't tolerate. Here's a snippet which adds a simple contains(str) method to your arsenal:

$.fn.contains = function (target) {
  var result = null;
  $(this).each(function (index, item) {
    if (item === target) {
      result = item;
    }
  });
  return result ? result : false;
}

Similarly, you could wrap $.inArray in an extension:

$.fn.contains = function (target) {
  return ($.inArray(target, this) > -1);
}
2012/12/31

Source: https://stackoverflow.com/questions/6116474
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