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MySQL COUNT DISTINCT


Question

I'm trying to collect the number of distinct visits in my cp yesterday, then count them.

SELECT
    DISTINCT `user_id` as user,
    `site_id` as site,
    `ts` as time
FROM
    `cp_visits`
WHERE
    ts >= DATE_SUB(NOW(), INTERVAL 1 DAY)

For some reason this is pulling multiple results with the same site id....how do i only pull and count the distinct site_id cp logins?

2015/11/20
1
145
11/20/2015 12:05:40 PM

Accepted Answer

 Select
     Count(Distinct user_id) As countUsers
   , Count(site_id) As countVisits
   , site_id As site
 From cp_visits
 Where ts >= DATE_SUB(NOW(), INTERVAL 1 DAY)
 Group By site_id
2011/04/20
299
4/20/2011 11:15:12 PM

Overall

SELECT
       COUNT(DISTINCT `site_id`) as distinct_sites
  FROM `cp_visits`
 WHERE ts >= DATE_SUB(NOW(), INTERVAL 1 DAY)

Or per site

  SELECT
         `site_id` as site,
         COUNT(DISTINCT `user_id`) as distinct_users_per_site
    FROM `cp_visits`
   WHERE ts >= DATE_SUB(NOW(), INTERVAL 1 DAY)
GROUP BY `site_id`

Having the time column in the result doesn't make sense - since you are aggregating the rows, showing one particular time is irrelevant, unless it is the min or max you are after.

2011/04/20

You need to use a group by clause.

SELECT  site_id, MAX(ts) as TIME, count(*) group by site_id
2011/04/20

Source: https://stackoverflow.com/questions/5737628
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