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How to print a percentage value in python?


Question

this is my code:

print str(float(1/3))+'%'

and it shows:

0.0%

but I want to get 33%

What can I do?

2019/11/08
1
187
11/8/2019 9:28:33 PM

Accepted Answer

format supports a percentage floating point precision type:

>>> print "{0:.0%}".format(1./3)
33%

If you don't want integer division, you can import Python3's division from __future__:

>>> from __future__ import division
>>> 1 / 3
0.3333333333333333

# The above 33% example would could now be written without the explicit
# float conversion:
>>> print "{0:.0f}%".format(1/3 * 100)
33%

# Or even shorter using the format mini language:
>>> print "{:.0%}".format(1/3)
33%
2018/05/24
285
5/24/2018 12:41:46 AM


Just for the sake of completeness, since I noticed no one suggested this simple approach:

>>> print("%.0f%%" % (100 * 1.0/3))
33%

Details:

  • %.0f stands for "print a float with 0 decimal places", so %.2f would print 33.33
  • %% prints a literal %. A bit cleaner than your original +'%'
  • 1.0 instead of 1 takes care of coercing the division to float, so no more 0.0
2018/10/25

You are dividing integers then converting to float. Divide by floats instead.

As a bonus, use the awesome string formatting methods described here: http://docs.python.org/library/string.html#format-specification-mini-language

To specify a percent conversion and precision.

>>> float(1) / float(3)
[Out] 0.33333333333333331

>>> 1.0/3.0
[Out] 0.33333333333333331

>>> '{0:.0%}'.format(1.0/3.0) # use string formatting to specify precision
[Out] '33%'

>>> '{percent:.2%}'.format(percent=1.0/3.0)
[Out] '33.33%'

A great gem!


Just to add Python 3 f-string solution

prob = 1.0/3.0
print(f"{prob:.0%}")
2019/09/24

Then you'd want to do this instead:

print str(int(1.0/3.0*100))+'%'

The .0 denotes them as floats and int() rounds them to integers afterwards again.

2011/03/15

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