Convert timestamp to readable date/time PHP
I have a timestamp stored in a session (1299446702).
How can I convert that to a readable date/time in PHP? I have tried srttotime, etc. to no avail.
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strtotime makes a date string into a timestamp. You want to do the opposite, which is date. The typical mysql date format is
date('Y-m-d H:i:s'); Check the manual page for what other letters represent.
If you have a timestamp that you want to use (apparently you do), it is the second argument of
I just added H:i:s to Rocket's answer to get the time along with the date.
echo date('m/d/Y H:i:s', 1299446702);
Output: 03/06/2011 16:25:02
$timestamp = 1465298940; $datetimeFormat = 'Y-m-d H:i:s'; $date = new \DateTime(); // If you must have use time zones // $date = new \DateTime('now', new \DateTimeZone('Europe/Helsinki')); $date->setTimestamp($timestamp); echo $date->format($datetimeFormat);
result: 2016-06-07 14:29:00
Other time zones:
If you are using PHP
date(), you can use this code to get the date, time, second, etc.
$time = time(); // you have 1299446702 in time $year = $time/31556926 % 12; // to get year $week = $time / 604800 % 52; // to get weeks $hour = $time / 3600 % 24; // to get hours $minute = $time / 60 % 60; // to get minutes $second = $time % 60; // to get seconds
I know that's an old one question, but its high in the search results.
If anyone wants timestamp conversion directly to a DateTime object, there's a simple one-liner:
$timestamp = 1299446702; $date = DateTime::createFromFormat('U', $timestamp);
Following @sromero comment, timezone parameter (the 3rd param in DateTime::createFromFormat()) is ignored when unix timestamp is passed, so the below code is unnecessary.
$date = DateTime::createFromFormat('U', $timestamp, new DateTimeZone('UTC'); // not needed, 3rd parameter is ignored
You may check PHP's manual for DateTime::createFromFormat for more info and options.