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how to open a url in python


Question

import urllib

fun open():
    return urllib.urlopen('http://example.com')

But when example.com opens it does not render css or js. How can I open the webpage in a web browser?

@error(404)
def error404(error):
    return webbrowser.open('http://example.com')

I am using bottle. Giving me the error: TypeError("'bool' object is not iterable",)

2014/03/03
1
82
3/3/2014 4:15:10 PM

Accepted Answer

with the webbrowser module

import webbrowser

webbrowser.open('http://example.com')  # Go to example.com
2016/07/15
179
7/15/2016 8:44:34 PM

import webbrowser  
webbrowser.open(url, new=0, autoraise=True)

Display url using the default browser. If new is 0, the url is opened in the same browser window if possible. If new is 1, a new browser window is opened if possible. If new is 2, a new browser page (“tab”) is opened if possible. If autoraise is True, the window is raised

webbrowser.open_new(url)

Open url in a new window of the default browser

webbrowser.open_new_tab(url)

Open url in a new page (“tab”) of the default browser

2013/09/25

On window

import os
os.system("start \"\" https://example.com")

On macOS

import os
os.system("open \"\" https://example.com")

On Linux

import os
os.system("xdg-open \"\" https://example.com")

Cross-Platform

import webbrowser

webbrowser.open('https://example.com')
2018/09/11

You have to read the data too.

Check out : http://www.doughellmann.com/PyMOTW/urllib2/ to understand it.

response = urllib2.urlopen(..)
headers = response.info()
data = response.read()

Of course, what you want is to render it in browser and aaronasterling's answer is what you want.

2010/11/29

You could also try:

import os
os.system("start \"\" http://example.com")

This, other than @aaronasterling ´s answer has the advantage that it opens the default web browser. Be sure not to forget the "http://".

2016/02/20

Here is another way to do it.

import webbrowser

webbrowser.open("foobar.com")
2019/01/13

Source: https://stackoverflow.com/questions/4302027
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