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How to create a dynamic array of integers


Question

How to create a dynamic array of integers in C++ using the new keyword?

2014/07/25
1
82
7/25/2014 12:45:48 PM

Accepted Answer

int main()
{
  int size;

  std::cin >> size;

  int *array = new int[size];

  delete [] array;

  return 0;
}

Don't forget to delete every array you allocate with new.

2010/10/27
121
10/27/2010 4:06:44 AM


You might want to consider using the Standard Template Library . It's simple and easy to use, plus you don't have to worry about memory allocations.

http://www.cplusplus.com/reference/stl/vector/vector/

int size = 5;                    // declare the size of the vector
vector<int> myvector(size, 0);   // create a vector to hold "size" int's
                                 // all initialized to zero
myvector[0] = 1234;              // assign values like a c++ array
2010/10/27

int* array = new int[size];
2010/10/27

As soon as question is about dynamic array you may want not just to create array with variable size, but also to change it's size during runtime. Here is an example with memcpy, you can use memcpy_s or std::copy as well. Depending on compiler, <memory.h> or <string.h> may be required. When using this functions you allocate new memory region, copy values of original memory regions to it and then release them.

//    create desired array dynamically
size_t length;
length = 100; //for example
int *array = new int[length];

//   now let's change is's size - e.g. add 50 new elements
size_t added = 50;
int *added_array = new int[added];

/*   
somehow set values to given arrays
*/ 

//    add elements to array
int* temp = new int[length + added];
memcpy(temp, array, length * sizeof(int));
memcpy(temp + length, added_array, added * sizeof(int));
delete[] array;
array = temp;

You may use constant 4 instead of sizeof(int).

2015/12/31

dynamically allocate some memory using new:

int* array = new int[SIZE];
2015/04/24

#include <stdio.h>
#include <cstring>
#include <iostream>

using namespace std;

int main()
{

    float arr[2095879];
    long k,i;
    char ch[100];
    k=0;

    do{
        cin>>ch;
        arr[k]=atof(ch);
        k++;
     }while(ch[0]=='0');

    cout<<"Array output"<<endl;
    for(i=0;i<k;i++){
        cout<<arr[i]<<endl;
    }

    return 0;
}

The above code works, the maximum float or int array size that could be defined was with size 2095879, and exit condition would be non zero beginning input number

2020/06/08

Source: https://stackoverflow.com/questions/4029870
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