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Concatenate a vector of strings/character


Question

If I have a vector of type character, how can I concatenate the values into string? Here's how I would do it with paste():

sdata = c('a', 'b', 'c')
paste(sdata[1], sdata[2], sdata[3], sep ='')

yielding "abc".

But of course, that only works if I know the length of sdata ahead of time.

2018/11/06
1
281
11/6/2018 10:45:53 AM

Accepted Answer

Try using an empty collapse argument within the paste function:

paste(sdata, collapse = '')

Thanks to http://twitter.com/onelinetips/status/7491806343

2010/01/20
491
1/20/2010 1:21:13 AM

Matt's answer is definitely the right answer. However, here's an alternative solution for comic relief purposes:

do.call(paste, c(as.list(sdata), sep = ""))
2017/10/13

You can use stri_paste function with collapse parameter from stringi package like this:

stri_paste(letters, collapse='')
## [1] "abcdefghijklmnopqrstuvwxyz" 

And some benchmarks:

require(microbenchmark)
test <- stri_rand_lipsum(100)
microbenchmark(stri_paste(test, collapse=''), paste(test,collapse=''), do.call(paste, c(as.list(test), sep="")))
Unit: microseconds
                                      expr     min       lq     mean   median       uq     max neval
           stri_paste(test, collapse = "") 137.477 139.6040 155.8157 148.5810 163.5375 226.171   100
                paste(test, collapse = "") 404.139 406.4100 446.0270 432.3250 442.9825 723.793   100
do.call(paste, c(as.list(test), sep = "")) 216.937 226.0265 251.6779 237.3945 264.8935 405.989   100
2017/08/17

For sdata:

gsub(", ","",toString(sdata))

For a vector of integers:

gsub(", ","",toString(c(1:10)))
2013/11/15

Matt Turner's answer is definitely the right answer. However, in the spirit of Ken Williams' answer, you could also do:

capture.output(cat(sdata, sep="")) 
2016/03/18

Here is a little utility function that collapses a named or unnamed list of values to a single string for easier printing. It will also print the code line itself. It's from my list examples in R page.

Generate some lists named or unnamed:

# Define Lists
ls_num <- list(1,2,3)
ls_str <- list('1','2','3')
ls_num_str <- list(1,2,'3')

# Named Lists
ar_st_names <- c('e1','e2','e3')
ls_num_str_named <- ls_num_str
names(ls_num_str_named) <- ar_st_names

# Add Element to Named List
ls_num_str_named$e4 <- 'this is added'

Here is the a function that will convert named or unnamed list to string:

ffi_lst2str <- function(ls_list, st_desc, bl_print=TRUE) {

  # string desc
  if(missing(st_desc)){
    st_desc <- deparse(substitute(ls_list))
  }

  # create string
  st_string_from_list = paste0(paste0(st_desc, ':'), 
                               paste(names(ls_list), ls_list, sep="=", collapse=";" ))

  if (bl_print){
    print(st_string_from_list)
  }
}

Testing the function with the lists created prior:

> ffi_lst2str(ls_num)
[1] "ls_num:=1;=2;=3"
> ffi_lst2str(ls_str)
[1] "ls_str:=1;=2;=3"
> ffi_lst2str(ls_num_str)
[1] "ls_num_str:=1;=2;=3"
> ffi_lst2str(ls_num_str_named)
[1] "ls_num_str_named:e1=1;e2=2;e3=3;e4=this is added"

Testing the function with subset of list elements:

> ffi_lst2str(ls_num_str_named[c('e2','e3','e4')])
[1] "ls_num_str_named[c(\"e2\", \"e3\", \"e4\")]:e2=2;e3=3;e4=this is added"
> ffi_lst2str(ls_num[2:3])
[1] "ls_num[2:3]:=2;=3"
> ffi_lst2str(ls_str[2:3])
[1] "ls_str[2:3]:=2;=3"
> ffi_lst2str(ls_num_str[2:4])
[1] "ls_num_str[2:4]:=2;=3;=NULL"
> ffi_lst2str(ls_num_str_named[c('e2','e3','e4')])
[1] "ls_num_str_named[c(\"e2\", \"e3\", \"e4\")]:e2=2;e3=3;e4=this is added"
2020/05/14

Source: https://stackoverflow.com/questions/2098368
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